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Simplifying layer visibility handling

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Instead of adding and removing the Google container, we just toggle
style.display. This also removes the unused rendered and displayed
properties of the cache.
This commit is contained in:
ahocevar
2013-04-04 11:40:21 +02:00
parent aaabdbc803
commit f0ef4728d8
1 changed files with 6 additions and 18 deletions
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24
lib/OpenLayers/Layer/Google/v3.js
View File

@@ -92,6 +92,7 @@ OpenLayers.Layer.Google.v3 = {
googleControl.style.width = '100%';
googleControl.style.height = '100%';
mapObject.controls[google.maps.ControlPosition.TOP_LEFT].push(googleControl);
this.map.div.appendChild(container);
// cache elements for use by any other google layers added to
// this same map
@@ -140,26 +141,13 @@ OpenLayers.Layer.Google.v3 = {
}
var container = this.mapObject.getDiv();
if (visible === true) {
if (container.parentNode !== map.div) {
map.div.appendChild(container);
if (!cache.rendered) {
google.maps.event.addListenerOnce(this.mapObject, 'tilesloaded', function() {
cache.googleControl.appendChild(map.viewPortDiv);
cache.rendered = true;
});
} else {
cache.googleControl.appendChild(map.viewPortDiv);
}
google.maps.event.trigger(this.mapObject, 'resize');
}
container.style.display = '';
cache.googleControl.appendChild(map.viewPortDiv);
google.maps.event.trigger(this.mapObject, 'resize');
this.mapObject.setMapTypeId(type);
cache.displayed = this.id;
} else {
if (cache.googleControl.hasChildNodes()) {
map.div.appendChild(map.viewPortDiv);
map.div.removeChild(container);
}
delete cache.displayed;
map.div.appendChild(map.viewPortDiv);
container.style.display = 'none';
}
}
},