Making it so you can remove more points from a linear ring. p=gregers, r=me (closes #2172)

git-svn-id: http://svn.openlayers.org/trunk/openlayers@11819 dc9f47b5-9b13-0410-9fdd-eb0c1a62fdaf
This commit is contained in:
Tim Schaub
2011-03-30 23:54:54 +00:00
parent 587b2320ab
commit b8ba064ede
2 changed files with 5 additions and 5 deletions

View File

@@ -93,7 +93,7 @@ OpenLayers.Geometry.LinearRing = OpenLayers.Class(
* point - {<OpenLayers.Geometry.Point>}
*/
removeComponent: function(point) {
if (this.components.length > 4) {
if (this.components.length > 3) {
//remove last point
this.components.pop();

View File

@@ -58,7 +58,7 @@
}
function test_LinearRing_removeComponent(t) {
t.plan(11);
t.plan(10);
var components = [new OpenLayers.Geometry.Point(0,0),
new OpenLayers.Geometry.Point(0,10),
@@ -71,7 +71,7 @@
t.eq(ring.components.length, 4, "removing from linear ring with 5 points: length ok");
t.ok(ring.components[0].equals(components[0]), "point one correct");
t.ok(ring.components[1].equals(components[1]), "point two correct");
t.ok(ring.components[2].equals(components[3]), "point one correct");
t.ok(ring.components[2].equals(components[3]), "point three correct");
t.ok(ring.components[0] === ring.components[ring.components.length - 1],
"first and last point are the same");
@@ -80,10 +80,10 @@
t.ok(ringBounds.equals(testBounds), "bounds correctly recalculated");
ring.removeComponent( ring.components[2] );
t.eq(ring.components.length, 4, "cant remove from linear ring with only 4 points. new length ok (unchanged)");
ring.removeComponent( ring.components[1] );
t.eq(ring.components.length, 3, "cant remove from linear ring with only 3 points. new length ok");
t.ok(ring.components[0].equals(components[0]), "point one correct");
t.ok(ring.components[1].equals(components[1]), "point two correct");
t.ok(ring.components[2].equals(components[3]), "point one correct");
t.ok(ring.components[0] === ring.components[ring.components.length - 1],
"first and last point are the same");