Comment only. A bit of documentation for distVincenty.
git-svn-id: http://svn.openlayers.org/trunk/openlayers@7973 dc9f47b5-9b13-0410-9fdd-eb0c1a62fdaf
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@@ -796,13 +796,18 @@ OpenLayers.Util.rad = function(x) {return x*Math.PI/180;};
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/**
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/**
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* Function: distVincenty
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* Function: distVincenty
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* Given two objects representing points with geographic coordinates, this
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* calculates the distance between those points on the surface of an
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* ellipsoid.
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*
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*
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* Parameters:
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* Parameters:
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* p1 - {<OpenLayers.LonLat>} (or any object with both .lat, .lon properties)
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* p1 - {<OpenLayers.LonLat>} (or any object with both .lat, .lon properties)
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* p2 - {<OpenLayers.LonLat>} (or any object with both .lat, .lon properties)
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* p2 - {<OpenLayers.LonLat>} (or any object with both .lat, .lon properties)
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*
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*
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* Returns:
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* Returns:
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* {Float}
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* {Float} The distance (in km) between the two input points as measured on an
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* ellipsoid. Note that the input point objects must be in geographic
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* coordinates (decimal degrees) and the return distance is in kilometers.
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*/
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*/
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OpenLayers.Util.distVincenty=function(p1, p2) {
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OpenLayers.Util.distVincenty=function(p1, p2) {
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var a = 6378137, b = 6356752.3142, f = 1/298.257223563;
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var a = 6378137, b = 6356752.3142, f = 1/298.257223563;
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