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Accept an expression string for rule filter

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This commit is contained in:
Tim Schaub
2013-06-17 17:30:44 -06:00
parent 38b784d672
commit a663d8fcae
6 changed files with 30 additions and 22 deletions
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13
examples/style-rules.js
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@@ -3,9 +3,6 @@ goog.require('ol.RendererHint');
goog.require('ol.View2D');
goog.require('ol.control.defaults');
goog.require('ol.expression');
goog.require('ol.filter.Filter');
goog.require('ol.filter.Geometry');
goog.require('ol.geom.GeometryType');
goog.require('ol.layer.Vector');
goog.require('ol.parser.GeoJSON');
goog.require('ol.proj');
@@ -19,9 +16,7 @@ goog.require('ol.style.Text');
var style = new ol.style.Style({rules: [
new ol.style.Rule({
filter: new ol.filter.Filter(function(feature) {
return feature.get('where') == 'outer';
}),
filter: 'where == "outer"',
symbolizers: [
new ol.style.Line({
strokeColor: ol.expression.parse('color'),
@@ -31,9 +26,7 @@ var style = new ol.style.Style({rules: [
]
}),
new ol.style.Rule({
filter: new ol.filter.Filter(function(feature) {
return feature.get('where') == 'inner';
}),
filter: 'where == "inner"',
symbolizers: [
new ol.style.Line({
strokeColor: '#013',
@@ -48,7 +41,7 @@ var style = new ol.style.Style({rules: [
]
}),
new ol.style.Rule({
filter: new ol.filter.Geometry(ol.geom.GeometryType.POINT),
filter: 'geometryType("point")',
symbolizers: [
new ol.style.Shape({
size: 40,