Make MapServer multi-url selection deterministic. (Closes #803)

git-svn-id: http://svn.openlayers.org/trunk/openlayers@5622 dc9f47b5-9b13-0410-9fdd-eb0c1a62fdaf
This commit is contained in:
crschmidt
2008-01-02 15:23:45 +00:00
parent 09e0d3ec81
commit 67e260775e
2 changed files with 31 additions and 13 deletions
+13 -10
View File
@@ -144,19 +144,19 @@ OpenLayers.Layer.MapServer = OpenLayers.Class(OpenLayers.Layer.Grid, {
// use layer's url unless altUrl passed in
var url = (altUrl == null) ? this.url : altUrl;
// if url is not a string, it should be an array of strings,
// in which case we will randomly select one of them in order
// to evenly distribute requests to different urls.
if (typeof url == "object") {
url = url[Math.floor(Math.random()*url.length)];
}
// requestString always starts with url
var requestString = url;
// create a new params hashtable with all the layer params and the
// new params together. then convert to string
var allParams = OpenLayers.Util.extend({}, this.params);
allParams = OpenLayers.Util.extend(allParams, newParams);
var paramsString = OpenLayers.Util.getParameterString(allParams);
// if url is not a string, it should be an array of strings,
// in which case we will deterministically select one of them in
// order to evenly distribute requests to different urls.
if (url instanceof Array) {
url = this.selectUrl(paramsString, url);
}
// ignore parameters that are already in the url search string
var urlParams = OpenLayers.Util.upperCaseObject(
OpenLayers.Util.getParameters(url));
@@ -165,8 +165,11 @@ OpenLayers.Layer.MapServer = OpenLayers.Class(OpenLayers.Layer.Grid, {
delete allParams[key];
}
}
var paramsString = OpenLayers.Util.getParameterString(allParams);
paramsString = OpenLayers.Util.getParameterString(allParams);
// requestString always starts with url
var requestString = url;
// MapServer needs '+' seperating things like bounds/height/width.
// Since typically this is URL encoded, we use a slight hack: we
// depend on the list-like functionality of getParameterString to