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Add style property "display" to vector feature style. If display is "none" the feature won't be rendered and there's a DOM node for that feature it'll be removed. Commiting this on behalf of ahocevar. Thanks Andreas for the patch. r=crschmidt. (closes #1173).

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git-svn-id: http://svn.openlayers.org/trunk/openlayers@5541 dc9f47b5-9b13-0410-9fdd-eb0c1a62fdaf
This commit is contained in:
Éric Lemoine
2007-12-20 19:20:23 +00:00
parent 2d1099d60d
commit 2931cd3065
3 changed files with 31 additions and 13 deletions
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tests/Renderer/test_Elements.html
+12 -2
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@@ -103,7 +103,7 @@
}
function test_Elements_drawGeometry(t) {
t.plan(4);
t.plan(5);
OpenLayers.Renderer.Elements.prototype._initialize =
OpenLayers.Renderer.Elements.prototype.initialize;
@@ -138,7 +138,17 @@
t.eq(g_Node._featureId, 'dude', "_featureId is correct");
t.ok(g_Node._style, "_style is correct");
t.eq(g_Node._geometryClass, 'bar', "_geometryClass is correct");
var _getElement = OpenLayers.Util.getElement;
OpenLayers.Util.getElement = function(id) {
return g_Node;
}
var style = {'display':'none'};
r.drawGeometry(geometry, style, featureId);
t.ok(g_Node.parentNode != r.root, "node is correctly removed");
OpenLayers.Util.getElement = _getElement;
OpenLayers.Renderer.Elements.prototype.initialize =
OpenLayers.Renderer.Elements.prototype._initialize;
}